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(I)=I2-1
We move all terms to the left:
(I)-(I2-1)=0
We add all the numbers together, and all the variables
-(+I^2-1)+I=0
We get rid of parentheses
-I^2+I+1=0
We add all the numbers together, and all the variables
-1I^2+I+1=0
a = -1; b = 1; c = +1;
Δ = b2-4ac
Δ = 12-4·(-1)·1
Δ = 5
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$I_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$I_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$I_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{5}}{2*-1}=\frac{-1-\sqrt{5}}{-2} $$I_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{5}}{2*-1}=\frac{-1+\sqrt{5}}{-2} $
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