I(z+4)-6=10(5-z

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Solution for I(z+4)-6=10(5-z equation: 



(I+4)-6=10(5-I

We move all terms to the left:

(I+4)-6-(10(5-I)=0

We add all the numbers together, and all the variables

(I+4)-(10(-1I+5)-6=0

We get rid of parentheses

I-(10(-1I+5)-6+4=0

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