I-9+3(4u+2)=-5(u+1)

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Solution for I-9+3(4u+2)=-5(u+1) equation: 



-9+3(4I+2)=-5(I+1)

We move all terms to the left:

-9+3(4I+2)-(-5(I+1))=0

We multiply parentheses

12I-(-5(I+1))+6-9=0



We calculate terms in parentheses: -(-5(I+1)), so:

-5(I+1)

We multiply parentheses

-5I-5

Back to the equation:

-(-5I-5)



We add all the numbers together, and all the variables

12I-(-5I-5)-3=0

We get rid of parentheses

12I+5I+5-3=0

We add all the numbers together, and all the variables

17I+2=0

We move all terms containing I to the left, all other terms to the right

17I=-2

I=-2/17

I=-2/17

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