I.1x=0.2(x+2)

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Solution for I.1x=0.2(x+2) equation: 



.1I=0.2(I+2)

We move all terms to the left:

.1I-(0.2(I+2))=0



We calculate terms in parentheses: -(0.2(I+2)), so:

0.2(I+2)

We multiply parentheses

0.2I+0.4

Back to the equation:

-(0.2I+0.4)



We get rid of parentheses

.1I-0.2I-0.4=0

We add all the numbers together, and all the variables

-0.1I-0.4=0

We move all terms containing I to the left, all other terms to the right

-0.1I=0.4

I=0.4/-0.1

I=-4

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