I/2(4x-10)+5=x-11

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Solution for I/2(4x-10)+5=x-11 equation: 



/2(4I-10)+5=I-11

We move all terms to the left:

/2(4I-10)+5-(I-11)=0



Domain of the equation: 2(4I-10)!=0

I∈R



We get rid of parentheses

/2(4I-10)-I+11+5=0

We multiply all the terms by the denominator


-I*2(4I-10)+11*2(4I-10)+5*2(4I-10)+=0

We add all the numbers together, and all the variables

-I*2(4I-10)+11*2(4I-10)+5*2(4I-10)=0

Wy multiply elements

-2I^2(4+22I(4+10I(4=0

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