I1/3(12x-24)=16

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Solution for I1/3(12x-24)=16 equation: 



1/3(12I-24)=16

We move all terms to the left:

1/3(12I-24)-(16)=0



Domain of the equation: 3(12I-24)!=0

I∈R



We multiply all the terms by the denominator


-16*3(12I-24)+1=0

Wy multiply elements

-48I(1+1=0

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