I2(4z-1)=3(z+2)

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Solution for I2(4z-1)=3(z+2) equation: 



2(4I-1)=3(I+2)

We move all terms to the left:

2(4I-1)-(3(I+2))=0

We multiply parentheses

8I-(3(I+2))-2=0



We calculate terms in parentheses: -(3(I+2)), so:

3(I+2)

We multiply parentheses

3I+6

Back to the equation:

-(3I+6)



We get rid of parentheses

8I-3I-6-2=0

We add all the numbers together, and all the variables

5I-8=0

We move all terms containing I to the left, all other terms to the right

5I=8

I=8/5

I=1+3/5

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