I2x+12I=4x

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Solution for I2x+12I=4x equation: 



2I+12=4I

We move all terms to the left:

2I+12-(4I)=0

We add all the numbers together, and all the variables

-2I+12=0

We move all terms containing I to the left, all other terms to the right

-2I=-12

I=-12/-2

I=+6

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