I2x+1I=4x+3

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Solution for I2x+1I=4x+3 equation: 



2I+1=4I+3

We move all terms to the left:

2I+1-(4I+3)=0

We get rid of parentheses

2I-4I-3+1=0

We add all the numbers together, and all the variables

-2I-2=0

We move all terms containing I to the left, all other terms to the right

-2I=2

I=2/-2

I=-1

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