I2x+3(x-5)=15

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Solution for I2x+3(x-5)=15 equation:



2I+3(I-5)=15
We move all terms to the left:
2I+3(I-5)-(15)=0
We multiply parentheses
2I+3I-15-15=0
We add all the numbers together, and all the variables
5I-30=0
We move all terms containing I to the left, all other terms to the right
5I=30
I=30/5
I=6

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