I2x+4I=2(x+6)

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Solution for I2x+4I=2(x+6) equation: 



2I+4=2(I+6)

We move all terms to the left:

2I+4-(2(I+6))=0



We calculate terms in parentheses: -(2(I+6)), so:

2(I+6)

We multiply parentheses

2I+12

Back to the equation:

-(2I+12)



We get rid of parentheses

2I-2I-12+4=0

We add all the numbers together, and all the variables

-8!=0

There is no solution for this equation

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