I3(2r-14)-3r=13(r-4)

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Solution for I3(2r-14)-3r=13(r-4) equation: 



3(2I-14)-3I=13(I-4)

We move all terms to the left:

3(2I-14)-3I-(13(I-4))=0

We add all the numbers together, and all the variables

-3I+3(2I-14)-(13(I-4))=0

We multiply parentheses

-3I+6I-(13(I-4))-42=0



We calculate terms in parentheses: -(13(I-4)), so:

13(I-4)

We multiply parentheses

13I-52

Back to the equation:

-(13I-52)



We add all the numbers together, and all the variables

3I-(13I-52)-42=0

We get rid of parentheses

3I-13I+52-42=0

We add all the numbers together, and all the variables

-10I+10=0

We move all terms containing I to the left, all other terms to the right

-10I=-10

I=-10/-10

I=1

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