I3(2x-6)=2(2x+1

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Solution for I3(2x-6)=2(2x+1 equation: 



3(2I-6)=2(2I+1

We move all terms to the left:

3(2I-6)-(2(2I+1)=0

We multiply parentheses

6I-(2(2I+1)-18=0

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