I32/(x+3)=36/(x+6)

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Solution for I32/(x+3)=36/(x+6) equation: 



32/(I+3)=36/(I+6)

We move all terms to the left:

32/(I+3)-(36/(I+6))=0



Domain of the equation: (I+3)!=0

We move all terms containing I to the left, all other terms to the right

I!=-3

I∈R





Domain of the equation: (I+6))!=0

I∈R



We calculate fractions


32I/((I+3)*(I+6)))+(-(36*(I+3))/((I+3)*(I+6)))=0



We calculate terms in parentheses: -(36*(I+3))/((I+3)*(I+6))), so:

36*(I+3))/((I+3)*(I+6))

We multiply all the terms by the denominator


36*(I+3))

We multiply parentheses

36I+

We add all the numbers together, and all the variables

36I

Back to the equation:

-(36I)



We add all the numbers together, and all the variables

-36I+32I/((I+3)*(I+6)))+(=0

We multiply all the terms by the denominator


-36I*((I+3)*(I+6)))+(+32I=0

We add all the numbers together, and all the variables

32I-36I*((I+3)*(I+6)))+(=0

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