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4(2I+3)-15=5I-10
We move all terms to the left:
4(2I+3)-15-(5I-10)=0
We multiply parentheses
8I-(5I-10)+12-15=0
We get rid of parentheses
8I-5I+10+12-15=0
We add all the numbers together, and all the variables
3I+7=0
We move all terms containing I to the left, all other terms to the right
3I=-7
I=-7/3
I=-2+1/3
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