I4(z-2)+z=-13

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Solution for I4(z-2)+z=-13 equation: 



4(I-2)+I=-13

We move all terms to the left:

4(I-2)+I-(-13)=0

We add all the numbers together, and all the variables

I+4(I-2)+13=0

We multiply parentheses

I+4I-8+13=0

We add all the numbers together, and all the variables

5I+5=0

We move all terms containing I to the left, all other terms to the right

5I=-5

I=-5/5

I=-1

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