I80-x=10+2(90-x)

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Solution for I80-x=10+2(90-x) equation: 



80-I=10+2(90-I)

We move all terms to the left:

80-I-(10+2(90-I))=0

We add all the numbers together, and all the variables

-I-(10+2(-1I+90))+80=0

We add all the numbers together, and all the variables

-1I-(10+2(-1I+90))+80=0



We calculate terms in parentheses: -(10+2(-1I+90)), so:

10+2(-1I+90)

determiningTheFunctionDomain
2(-1I+90)+10

We multiply parentheses

-2I+180+10

We add all the numbers together, and all the variables

-2I+190

Back to the equation:

-(-2I+190)



We get rid of parentheses

-1I+2I-190+80=0

We add all the numbers together, and all the variables

I-110=0

We move all terms containing I to the left, all other terms to the right

I=110

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