I8x-3/3x=7

Solution for I8x-3/3x=7 equation:

8I-3/3I=7

We move all terms to the left:

8I-3/3I-(7)=0


Domain of the equation: 3I!=0

I!=0/3

I!=0

I∈R


We multiply all the terms by the denominator


8I*3I-7*3I-3=0

Wy multiply elements

24I^2-21I-3=0

a = 24; b = -21; c = -3;
Δ = b2-4ac
Δ = -212-4·24·(-3)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$I_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$I_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$I_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-27}{2*24}=\frac{-6}{48}
=-1/8
$
$I_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+27}{2*24}=\frac{48}{48}
=1
$