I=0.08x+(.18)(11000-x)

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Solution for I=0.08x+(.18)(11000-x) equation: 



=0.08I+(.18)(11000-I)

We move all terms to the left:

-(0.08I+(.18)(11000-I))=0

We add all the numbers together, and all the variables

-(0.08I+(0.18)(-1I+11000))=0

We multiply parentheses ..

-(0.08I+(-0.18I+1980))=0



We calculate terms in parentheses: -(0.08I+(-0.18I+1980)), so:

0.08I+(-0.18I+1980)

We get rid of parentheses

0.08I-0.18I+1980

We add all the numbers together, and all the variables

-0.1I+1980

Back to the equation:

-(-0.1I+1980)



We get rid of parentheses

0.1I-1980=0

We move all terms containing I to the left, all other terms to the right

0.1I=1980

I=1980/0.1

I=19800

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