In(x)+In(4x)-In(2x)=1

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Solution for In(x)+In(4x)-In(2x)=1 equation: 


Simplifying
In(x) + In(4x) + -1In(2x) = 1

Multiply nI * x
nxI + In(4x) + -1In(2x) = 1

Remove parenthesis around (4x)
nxI + nI * 4x + -1In(2x) = 1

Reorder the terms for easier multiplication:
nxI + 4nI * x + -1In(2x) = 1

Multiply nI * x
nxI + 4nxI + -1In(2x) = 1

Remove parenthesis around (2x)
nxI + 4nxI + -1nI * 2x = 1

Reorder the terms for easier multiplication:
nxI + 4nxI + -1 * 2nI * x = 1

Multiply -1 * 2
nxI + 4nxI + -2nI * x = 1

Multiply nI * x
nxI + 4nxI + -2nxI = 1

Combine like terms: nxI + 4nxI = 5nxI
5nxI + -2nxI = 1

Combine like terms: 5nxI + -2nxI = 3nxI
3nxI = 1

Solving
3nxI = 1

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Divide each side by '3xI'.
n = 0.3333333333x-1I-1

Simplifying
n = 0.3333333333x-1I-1

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