In(x)+in(4x)=2

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Solution for In(x)+in(4x)=2 equation:


Simplifying
In(x) + in(4x) = 2

Multiply nI * x
nxI + in(4x) = 2

Remove parenthesis around (4x)
nxI + in * 4x = 2

Reorder the terms for easier multiplication:
nxI + 4in * x = 2

Multiply in * x
nxI + 4inx = 2

Reorder the terms:
4inx + nxI = 2

Solving
4inx + nxI = 2

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1nxI' to each side of the equation.
4inx + nxI + -1nxI = 2 + -1nxI

Combine like terms: nxI + -1nxI = 0
4inx + 0 = 2 + -1nxI
4inx = 2 + -1nxI

Divide each side by '4nx'.
i = 0.5n-1x-1 + -0.25I

Simplifying
i = 0.5n-1x-1 + -0.25I

Reorder the terms:
i = -0.25I + 0.5n-1x-1

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