In(x)+in(x+1)=12

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Solution for In(x)+in(x+1)=12 equation:


Simplifying
In(x) + in(x + 1) = 12

Multiply nI * x
nxI + in(x + 1) = 12

Reorder the terms:
nxI + in(1 + x) = 12
nxI + (1 * in + x * in) = 12
nxI + (1in + inx) = 12

Reorder the terms:
1in + inx + nxI = 12

Solving
1in + inx + nxI = 12

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1nxI' to each side of the equation.
1in + inx + nxI + -1nxI = 12 + -1nxI

Combine like terms: nxI + -1nxI = 0
1in + inx + 0 = 12 + -1nxI
1in + inx = 12 + -1nxI

Reorder the terms:
-12 + 1in + inx + nxI = 12 + -1nxI + -12 + nxI

Reorder the terms:
-12 + 1in + inx + nxI = 12 + -12 + -1nxI + nxI

Combine like terms: 12 + -12 = 0
-12 + 1in + inx + nxI = 0 + -1nxI + nxI
-12 + 1in + inx + nxI = -1nxI + nxI

Combine like terms: -1nxI + nxI = 0
-12 + 1in + inx + nxI = 0

The solution to this equation could not be determined.

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