In(x+1)-(1nx)=2

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Solution for In(x+1)-(1nx)=2 equation: 


Simplifying
In(x + 1) + -1(1nx) = 2

Reorder the terms:
nI(1 + x) + -1(1nx) = 2
(1 * nI + x * nI) + -1(1nx) = 2
(1nI + nxI) + -1(1nx) = 2

Remove parenthesis around (1nx)
1nI + nxI + -1 * 1nx = 2

Multiply -1 * 1
1nI + nxI + -1nx = 2

Reorder the terms:
1nI + -1nx + nxI = 2

Solving
1nI + -1nx + nxI = 2

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Reorder the terms:
-2 + 1nI + -1nx + nxI = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + 1nI + -1nx + nxI = 0

The solution to this equation could not be determined.

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