In(x+3)+In(x-3)=2

Solution for In(x+3)+In(x-3)=2 equation:

Simplifying
In(x + 3) + In(x + -3) = 2

Reorder the terms:
nI(3 + x) + In(x + -3) = 2
(3 * nI + x * nI) + In(x + -3) = 2
(3nI + nxI) + In(x + -3) = 2

Reorder the terms:
3nI + nxI + nI(-3 + x) = 2
3nI + nxI + (-3 * nI + x * nI) = 2
3nI + nxI + (-3nI + nxI) = 2

Reorder the terms:
3nI + -3nI + nxI + nxI = 2

Combine like terms: 3nI + -3nI = 0
0 + nxI + nxI = 2
nxI + nxI = 2

Combine like terms: nxI + nxI = 2nxI
2nxI = 2

Solving
2nxI = 2

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Divide each side by '2xI'.
n = x-1I-1

Simplifying
n = x-1I-1