J(x)=3x+18/6

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Solution for J(x)=3x+18/6 equation: 



(J)=3J+18/6

We move all terms to the left:

(J)-(3J+18/6)=0

We add all the numbers together, and all the variables

J-(3J+3)=0

We get rid of parentheses

J-3J-3=0

We add all the numbers together, and all the variables

-2J-3=0

We move all terms containing J to the left, all other terms to the right

-2J=3

J=3/-2

J=-1+1/2

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