J+3(1+2j)=17

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Solution for J+3(1+2j)=17 equation: 



+3(1+2J)=17

We move all terms to the left:

+3(1+2J)-(17)=0

We add all the numbers together, and all the variables

3(2J+1)-17=0

We multiply parentheses

6J+3-17=0

We add all the numbers together, and all the variables

6J-14=0

We move all terms containing J to the left, all other terms to the right

6J=14

J=14/6

J=2+1/3

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