J+3(1+2j)=7

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Solution for J+3(1+2j)=7 equation: 



+3(1+2J)=7

We move all terms to the left:

+3(1+2J)-(7)=0

We add all the numbers together, and all the variables

3(2J+1)-7=0

We multiply parentheses

6J+3-7=0

We add all the numbers together, and all the variables

6J-4=0

We move all terms containing J to the left, all other terms to the right

6J=4

J=4/6

J=2/3

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