J-6=(1/2j)+3

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Solution for J-6=(1/2j)+3 equation: 



-6=(1/2J)+3

We move all terms to the left:

-6-((1/2J)+3)=0



Domain of the equation: 2J)+3)!=0

J!=0/1

J!=0

J∈R



We add all the numbers together, and all the variables

-((+1/2J)+3)-6=0

We multiply all the terms by the denominator


-((+1-6*2J)+3)=0



We calculate terms in parentheses: -((+1-6*2J)+3), so:

(+1-6*2J)+3

We add all the numbers together, and all the variables

(-6*2J+1)+3

We get rid of parentheses

-6*2J+1+3

We add all the numbers together, and all the variables

-6*2J+4

Wy multiply elements

-12J+4

Back to the equation:

-(-12J+4)



We get rid of parentheses

12J-4=0

We move all terms containing J to the left, all other terms to the right

12J=4

J=4/12

J=1/3

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