J=2x-5(-7-4x)

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Solution for J=2x-5(-7-4x) equation: 



=2J-5(-7-4J)

We move all terms to the left:

-(2J-5(-7-4J))=0

We add all the numbers together, and all the variables

-(2J-5(-4J-7))=0



We calculate terms in parentheses: -(2J-5(-4J-7)), so:

2J-5(-4J-7)

We multiply parentheses

2J+20J+35

We add all the numbers together, and all the variables

22J+35

Back to the equation:

-(22J+35)



We get rid of parentheses

-22J-35=0

We move all terms containing J to the left, all other terms to the right

-22J=35

J=35/-22

J=-1+13/22

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