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(2K+1/2)=1/2(6K+1)
We move all terms to the left:
(2K+1/2)-(1/2(6K+1))=0
Domain of the equation: 2(6K+1))!=0We add all the numbers together, and all the variables
K∈R
(+2K+1/2)-(1/2(6K+1))=0
We get rid of parentheses
2K-(1/2(6K+1))+1/2=0
We calculate fractions
2K=0
K=0/2
K=0
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