K(3-(-1))+2(-1-k)+4(k-3)=0

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Solution for K(3-(-1))+2(-1-k)+4(k-3)=0 equation: 



(3-(-1))+2(-1-K)+4(K-3)=0

We add all the numbers together, and all the variables

2(-1K-1)+4(K-3)+(3-(-1))=0

We add all the numbers together, and all the variables

2(-1K-1)+4(K-3)+4=0

We multiply parentheses

-2K+4K-2-12+4=0

We add all the numbers together, and all the variables

2K-10=0

We move all terms containing K to the left, all other terms to the right

2K=10

K=10/2

K=5

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