K+2=(K+1)-(3k+1)

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Solution for K+2=(K+1)-(3k+1) equation: 



+2=(+1)-(3K+1)

We move all terms to the left:

+2-((+1)-(3K+1))=0

We add all the numbers together, and all the variables

-(1-(3K+1))+2=0



We calculate terms in parentheses: -(1-(3K+1)), so:

1-(3K+1)

determiningTheFunctionDomain
-(3K+1)+1

We get rid of parentheses

-3K-1+1

We add all the numbers together, and all the variables

-3K

Back to the equation:

-(-3K)



We get rid of parentheses

3K+2=0

We move all terms containing K to the left, all other terms to the right

3K=-2

K=-2/3

K=-2/3

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