K+3(k+2)+14=2(k+5)+10

Solution for K+3(k+2)+14=2(k+5)+10 equation:

Simplifying
K + 3(k + 2) + 14 = 2(k + 5) + 10

Reorder the terms:
K + 3(2 + k) + 14 = 2(k + 5) + 10
K + (2 * 3 + k * 3) + 14 = 2(k + 5) + 10
K + (6 + 3k) + 14 = 2(k + 5) + 10

Reorder the terms:
6 + 14 + K + 3k = 2(k + 5) + 10

Combine like terms: 6 + 14 = 20
20 + K + 3k = 2(k + 5) + 10

Reorder the terms:
20 + K + 3k = 2(5 + k) + 10
20 + K + 3k = (5 * 2 + k * 2) + 10
20 + K + 3k = (10 + 2k) + 10

Reorder the terms:
20 + K + 3k = 10 + 10 + 2k

Combine like terms: 10 + 10 = 20
20 + K + 3k = 20 + 2k

Add '-20' to each side of the equation.
20 + K + -20 + 3k = 20 + -20 + 2k

Reorder the terms:
20 + -20 + K + 3k = 20 + -20 + 2k

Combine like terms: 20 + -20 = 0
0 + K + 3k = 20 + -20 + 2k
K + 3k = 20 + -20 + 2k

Combine like terms: 20 + -20 = 0
K + 3k = 0 + 2k
K + 3k = 2k

Solving
K + 3k = 2k

Solving for variable 'K'.

Move all terms containing K to the left, all other terms to the right.

Add '-3k' to each side of the equation.
K + 3k + -3k = 2k + -3k

Combine like terms: 3k + -3k = 0
K + 0 = 2k + -3k
K = 2k + -3k

Combine like terms: 2k + -3k = -1k
K = -1k

Simplifying
K = -1k