K=(2n+2-2n+4)/(2n+1-2n+2)

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Solution for K=(2n+2-2n+4)/(2n+1-2n+2) equation: 



=(2K+2-2K+4)/(2K+1-2K+2)

We move all terms to the left:

-((2K+2-2K+4)/(2K+1-2K+2))=0



Domain of the equation: (2K+1-2K+2))!=0

We move all terms containing K to the left, all other terms to the right

2K-2K+2)!=-1

K∈R



We add all the numbers together, and all the variables

-(6/3)=0

We get rid of parentheses

-6/3=0

We multiply all the terms by the denominator


-6!=0

There is no solution for this equation

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