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x in (-oo:+oo)
K = 2*b-(k*((5*w)/3)) // - 2*b-(k*((5*w)/3))
K-(2*b)+k*((5*w)/3) = 0
K-2*b+k*((5*w)/3) = 0
K-2*b+5/3*k*w = 0
x należy do R
x in (-oo:+oo)
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