K=3/2(k-9)

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Solution for K=3/2(k-9) equation: 


x in (-oo:+oo)

K = (3/2)*(k-9) // - (3/2)*(k-9)

K-((3/2)*(k-9)) = 0

(-3/2)*(k-9)+K = 0

K-3/2*(k-9) = 0

K-3/2*(k-9) = 0

K-3/2*k+27/2 = 0

K-3/2*k+27/2 = 0

x belongs to the empty set

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