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=5/9(K-32)+275.15
We move all terms to the left:
-(5/9(K-32)+275.15)=0
Domain of the equation: 9(K-32)+275.15)!=0We multiply all the terms by the denominator
K∈R
-(5=0
We add all the numbers together, and all the variables
=0
K=0/1
K=0
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