L3(z+7)=4(z+6)+9

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Solution for L3(z+7)=4(z+6)+9 equation: 



3(L+7)=4(L+6)+9

We move all terms to the left:

3(L+7)-(4(L+6)+9)=0

We multiply parentheses

3L-(4(L+6)+9)+21=0



We calculate terms in parentheses: -(4(L+6)+9), so:

4(L+6)+9

We multiply parentheses

4L+24+9

We add all the numbers together, and all the variables

4L+33

Back to the equation:

-(4L+33)



We get rid of parentheses

3L-4L-33+21=0

We add all the numbers together, and all the variables

-1L-12=0

We move all terms containing L to the left, all other terms to the right

-L=12

L=12/-1

L=-12

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