Ln(2x)+ln(3x-1)=4

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Solution for Ln(2x)+ln(3x-1)=4 equation: 


Simplifying
Ln(2x) + ln(3x + -1) = 4

Remove parenthesis around (2x)
nL * 2x + ln(3x + -1) = 4

Reorder the terms for easier multiplication:
2nL * x + ln(3x + -1) = 4

Multiply nL * x
2nxL + ln(3x + -1) = 4

Reorder the terms:
2nxL + ln(-1 + 3x) = 4
2nxL + (-1 * ln + 3x * ln) = 4
2nxL + (-1ln + 3lnx) = 4

Reorder the terms:
-1ln + 3lnx + 2nxL = 4

Solving
-1ln + 3lnx + 2nxL = 4

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-2nxL' to each side of the equation.
-1ln + 3lnx + 2nxL + -2nxL = 4 + -2nxL

Combine like terms: 2nxL + -2nxL = 0
-1ln + 3lnx + 0 = 4 + -2nxL
-1ln + 3lnx = 4 + -2nxL

Reorder the terms:
-4 + -1ln + 3lnx + 2nxL = 4 + -2nxL + -4 + 2nxL

Reorder the terms:
-4 + -1ln + 3lnx + 2nxL = 4 + -4 + -2nxL + 2nxL

Combine like terms: 4 + -4 = 0
-4 + -1ln + 3lnx + 2nxL = 0 + -2nxL + 2nxL
-4 + -1ln + 3lnx + 2nxL = -2nxL + 2nxL

Combine like terms: -2nxL + 2nxL = 0
-4 + -1ln + 3lnx + 2nxL = 0

The solution to this equation could not be determined.

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