Ln(abs(y-5))=4x+2

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Solution for Ln(abs(y-5))=4x+2 equation: 


Simplifying
Ln(abs(y + -5)) = 4x + 2

Reorder the terms:
nL(abs(-5 + y)) = 4x + 2
nL((-5 * abs + y * abs)) = 4x + 2
nL((-5abs + absy)) = 4x + 2
(-5abs * nL + absy * nL) = 4x + 2
(-5abnsL + abnsyL) = 4x + 2

Reorder the terms:
-5abnsL + abnsyL = 2 + 4x

Solving
-5abnsL + abnsyL = 2 + 4x

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Reorder the terms:
-2 + -5abnsL + abnsyL + -4x = 2 + 4x + -2 + -4x

Reorder the terms:
-2 + -5abnsL + abnsyL + -4x = 2 + -2 + 4x + -4x

Combine like terms: 2 + -2 = 0
-2 + -5abnsL + abnsyL + -4x = 0 + 4x + -4x
-2 + -5abnsL + abnsyL + -4x = 4x + -4x

Combine like terms: 4x + -4x = 0
-2 + -5abnsL + abnsyL + -4x = 0

The solution to this equation could not be determined.

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