Ln(x)+ln(2x)+ln(3x)=0

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Solution for Ln(x)+ln(2x)+ln(3x)=0 equation: 


Simplifying
Ln(x) + ln(2x) + ln(3x) = 0

Multiply nL * x
nxL + ln(2x) + ln(3x) = 0

Remove parenthesis around (2x)
nxL + ln * 2x + ln(3x) = 0

Reorder the terms for easier multiplication:
nxL + 2ln * x + ln(3x) = 0

Multiply ln * x
nxL + 2lnx + ln(3x) = 0

Remove parenthesis around (3x)
nxL + 2lnx + ln * 3x = 0

Reorder the terms for easier multiplication:
nxL + 2lnx + 3ln * x = 0

Multiply ln * x
nxL + 2lnx + 3lnx = 0

Reorder the terms:
2lnx + 3lnx + nxL = 0

Combine like terms: 2lnx + 3lnx = 5lnx
5lnx + nxL = 0

Solving
5lnx + nxL = 0

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-1nxL' to each side of the equation.
5lnx + nxL + -1nxL = 0 + -1nxL

Combine like terms: nxL + -1nxL = 0
5lnx + 0 = 0 + -1nxL
5lnx = 0 + -1nxL
Remove the zero:
5lnx = -1nxL

Divide each side by '5nx'.
l = -0.2L

Simplifying
l = -0.2L

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