Ln(x)+log(x+1)=1

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Solution for Ln(x)+log(x+1)=1 equation:


Simplifying
Ln(x) + log(x + 1) = 1

Multiply nL * x
nxL + log(x + 1) = 1

Reorder the terms:
nxL + glo(1 + x) = 1
nxL + (1 * glo + x * glo) = 1
nxL + (1glo + glox) = 1

Reorder the terms:
1glo + glox + nxL = 1

Solving
1glo + glox + nxL = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '-1nxL' to each side of the equation.
1glo + glox + nxL + -1nxL = 1 + -1nxL

Combine like terms: nxL + -1nxL = 0
1glo + glox + 0 = 1 + -1nxL
1glo + glox = 1 + -1nxL

Reorder the terms:
-1 + 1glo + glox + nxL = 1 + -1nxL + -1 + nxL

Reorder the terms:
-1 + 1glo + glox + nxL = 1 + -1 + -1nxL + nxL

Combine like terms: 1 + -1 = 0
-1 + 1glo + glox + nxL = 0 + -1nxL + nxL
-1 + 1glo + glox + nxL = -1nxL + nxL

Combine like terms: -1nxL + nxL = 0
-1 + 1glo + glox + nxL = 0

The solution to this equation could not be determined.

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