Log(1-x)-log(4+x)=1

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Solution for Log(1-x)-log(4+x)=1 equation: 


Simplifying
Log(1 + -1x) + -1log(4 + x) = 1
(1 * goL + -1x * goL) + -1log(4 + x) = 1
(1goL + -1goxL) + -1log(4 + x) = 1
1goL + -1goxL + (4 * -1glo + x * -1glo) = 1
1goL + -1goxL + (-4glo + -1glox) = 1

Reorder the terms:
-4glo + -1glox + 1goL + -1goxL = 1

Solving
-4glo + -1glox + 1goL + -1goxL = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-1 + -4glo + -1glox + 1goL + -1goxL = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + -4glo + -1glox + 1goL + -1goxL = 0

The solution to this equation could not be determined.

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