Log(12)x+log(12)(x-1)+1=2

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Solution for Log(12)x+log(12)(x-1)+1=2 equation:


Simplifying
Log(12) * x + log(12)(x + -1) + 1 = 2

Reorder the terms for easier multiplication:
12goL * x + log(12)(x + -1) + 1 = 2

Multiply goL * x
12goxL + log(12)(x + -1) + 1 = 2

Reorder the terms:
12goxL + glo * 12(-1 + x) + 1 = 2

Reorder the terms for easier multiplication:
12goxL + 12glo(-1 + x) + 1 = 2
12goxL + (-1 * 12glo + x * 12glo) + 1 = 2
12goxL + (-12glo + 12glox) + 1 = 2

Reorder the terms:
1 + -12glo + 12glox + 12goxL = 2

Solving
1 + -12glo + 12glox + 12goxL = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -12glo + 12glox + -1 + 12goxL = 2 + -1

Reorder the terms:
1 + -1 + -12glo + 12glox + 12goxL = 2 + -1

Combine like terms: 1 + -1 = 0
0 + -12glo + 12glox + 12goxL = 2 + -1
-12glo + 12glox + 12goxL = 2 + -1

Combine like terms: 2 + -1 = 1
-12glo + 12glox + 12goxL = 1

Reorder the terms:
-1 + -12glo + 12glox + 12goxL = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + -12glo + 12glox + 12goxL = 0

The solution to this equation could not be determined.

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