Log(2x-1)-log(x+5)=2

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Solution for Log(2x-1)-log(x+5)=2 equation: 


Simplifying
Log(2x + -1) + -1log(x + 5) = 2

Reorder the terms:
goL(-1 + 2x) + -1log(x + 5) = 2
(-1 * goL + 2x * goL) + -1log(x + 5) = 2
(-1goL + 2goxL) + -1log(x + 5) = 2

Reorder the terms:
-1goL + 2goxL + -1glo(5 + x) = 2
-1goL + 2goxL + (5 * -1glo + x * -1glo) = 2
-1goL + 2goxL + (-5glo + -1glox) = 2

Reorder the terms:
-5glo + -1glox + -1goL + 2goxL = 2

Solving
-5glo + -1glox + -1goL + 2goxL = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-2 + -5glo + -1glox + -1goL + 2goxL = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + -5glo + -1glox + -1goL + 2goxL = 0

The solution to this equation could not be determined.

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