Log(2y-1)=(5y+4)

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Solution for Log(2y-1)=(5y+4) equation: 


Simplifying
Log(2y + -1) = (5y + 4)

Reorder the terms:
goL(-1 + 2y) = (5y + 4)
(-1 * goL + 2y * goL) = (5y + 4)
(-1goL + 2goyL) = (5y + 4)

Reorder the terms:
-1goL + 2goyL = (4 + 5y)

Remove parenthesis around (4 + 5y)
-1goL + 2goyL = 4 + 5y

Solving
-1goL + 2goyL = 4 + 5y

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-4 + -1goL + 2goyL + -5y = 4 + 5y + -4 + -5y

Reorder the terms:
-4 + -1goL + 2goyL + -5y = 4 + -4 + 5y + -5y

Combine like terms: 4 + -4 = 0
-4 + -1goL + 2goyL + -5y = 0 + 5y + -5y
-4 + -1goL + 2goyL + -5y = 5y + -5y

Combine like terms: 5y + -5y = 0
-4 + -1goL + 2goyL + -5y = 0

The solution to this equation could not be determined.

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