Log(3x+1)-4=2

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Solution for Log(3x+1)-4=2 equation: 


Simplifying
Log(3x + 1) + -4 = 2

Reorder the terms:
goL(1 + 3x) + -4 = 2
(1 * goL + 3x * goL) + -4 = 2
(1goL + 3goxL) + -4 = 2

Reorder the terms:
-4 + 1goL + 3goxL = 2

Solving
-4 + 1goL + 3goxL = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 1goL + 4 + 3goxL = 2 + 4

Reorder the terms:
-4 + 4 + 1goL + 3goxL = 2 + 4

Combine like terms: -4 + 4 = 0
0 + 1goL + 3goxL = 2 + 4
1goL + 3goxL = 2 + 4

Combine like terms: 2 + 4 = 6
1goL + 3goxL = 6

Reorder the terms:
-6 + 1goL + 3goxL = 6 + -6

Combine like terms: 6 + -6 = 0
-6 + 1goL + 3goxL = 0

The solution to this equation could not be determined.

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