Log(3x+1)-log(x-2)=1

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Solution for Log(3x+1)-log(x-2)=1 equation: 


Simplifying
Log(3x + 1) + -1log(x + -2) = 1

Reorder the terms:
goL(1 + 3x) + -1log(x + -2) = 1
(1 * goL + 3x * goL) + -1log(x + -2) = 1
(1goL + 3goxL) + -1log(x + -2) = 1

Reorder the terms:
1goL + 3goxL + -1glo(-2 + x) = 1
1goL + 3goxL + (-2 * -1glo + x * -1glo) = 1
1goL + 3goxL + (2glo + -1glox) = 1

Reorder the terms:
2glo + -1glox + 1goL + 3goxL = 1

Solving
2glo + -1glox + 1goL + 3goxL = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-1 + 2glo + -1glox + 1goL + 3goxL = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 2glo + -1glox + 1goL + 3goxL = 0

The solution to this equation could not be determined.

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