Log(3x-4)-log(6x)=2

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Solution for Log(3x-4)-log(6x)=2 equation: 


Simplifying
Log(3x + -4) + -1log(6x) = 2

Reorder the terms:
goL(-4 + 3x) + -1log(6x) = 2
(-4 * goL + 3x * goL) + -1log(6x) = 2
(-4goL + 3goxL) + -1log(6x) = 2

Remove parenthesis around (6x)
-4goL + 3goxL + -1glo * 6x = 2

Reorder the terms for easier multiplication:
-4goL + 3goxL + -1 * 6glo * x = 2

Multiply -1 * 6
-4goL + 3goxL + -6glo * x = 2

Multiply glo * x
-4goL + 3goxL + -6glox = 2

Reorder the terms:
-6glox + -4goL + 3goxL = 2

Solving
-6glox + -4goL + 3goxL = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-2 + -6glox + -4goL + 3goxL = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + -6glox + -4goL + 3goxL = 0

The solution to this equation could not be determined.

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