Log(8x)+log(x+2)=1

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Solution for Log(8x)+log(x+2)=1 equation: 


Simplifying
Log(8x) + log(x + 2) = 1

Remove parenthesis around (8x)
goL * 8x + log(x + 2) = 1

Reorder the terms for easier multiplication:
8goL * x + log(x + 2) = 1

Multiply goL * x
8goxL + log(x + 2) = 1

Reorder the terms:
8goxL + glo(2 + x) = 1
8goxL + (2 * glo + x * glo) = 1
8goxL + (2glo + glox) = 1

Reorder the terms:
2glo + glox + 8goxL = 1

Solving
2glo + glox + 8goxL = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-1 + 2glo + glox + 8goxL = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 2glo + glox + 8goxL = 0

The solution to this equation could not be determined.

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